5(a+3)+4(a+2)=6(2a+5)-5(3a-2)

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Solution for 5(a+3)+4(a+2)=6(2a+5)-5(3a-2) equation:


5(a+3)+4(a+2)=6(2a+5)-5(3a-2)

We simplify the equation to the form, which is simple to understand
5(a+3)+4(a+2)=6(2a+5)-5(3a-2)

Reorder the terms in parentheses
+(+5a+15)+4*(a+2)=6*(2a+5)-5*(3a-2)

Remove unnecessary parentheses
+5a+15+4+*(+a+2+)=+6+*(+2a+5+)-5+*(+3a-2+)

Reorder the terms in parentheses
+5a+15+(+4a+8)=6*(2a+5)-5*(3a-2)

Remove unnecessary parentheses
+5a+15+4a+8=+6+*(+2a+5+)-5+*(+3a-2+)

Reorder the terms in parentheses
+5a+15+4a+8=+(+12a+30)-5*(3a-2)

Remove unnecessary parentheses
+5a+15+4a+8=+12a+30-5+*(+3a-2+)

Reorder the terms in parentheses
+5a+15+4a+8=+12a+30+(-15a+10)

Remove unnecessary parentheses
+5a+15+4a+8=+12a+30-15a+10

We move all terms containing a to the left and all other terms to the right.
+5a+4a-12a+15a=+30+10-15-8

We simplify left and right side of the equation.
+12a=+17

We divide both sides of the equation by 12 to get a.
a=1.41666666667

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