5(a+3)-8a=40-6(a+1)

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Solution for 5(a+3)-8a=40-6(a+1) equation: 



5(a+3)-8a=40-6(a+1)

We move all terms to the left:

5(a+3)-8a-(40-6(a+1))=0

We add all the numbers together, and all the variables

-8a+5(a+3)-(40-6(a+1))=0

We multiply parentheses

-8a+5a-(40-6(a+1))+15=0



We calculate terms in parentheses: -(40-6(a+1)), so:

40-6(a+1)

determiningTheFunctionDomain
-6(a+1)+40

We multiply parentheses

-6a-6+40

We add all the numbers together, and all the variables

-6a+34

Back to the equation:

-(-6a+34)



We add all the numbers together, and all the variables

-3a-(-6a+34)+15=0

We get rid of parentheses

-3a+6a-34+15=0

We add all the numbers together, and all the variables

3a-19=0

We move all terms containing a to the left, all other terms to the right

3a=19

a=19/3

a=6+1/3

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