5(a+3)-a=-(4a-6+1)

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Solution for 5(a+3)-a=-(4a-6+1) equation: 



5(a+3)-a=-(4a-6+1)

We move all terms to the left:

5(a+3)-a-(-(4a-6+1))=0

We add all the numbers together, and all the variables

5(a+3)-a-(-(4a-5))=0

We add all the numbers together, and all the variables

-1a+5(a+3)-(-(4a-5))=0

We multiply parentheses

-1a+5a-(-(4a-5))+15=0



We calculate terms in parentheses: -(-(4a-5)), so:

-(4a-5)

We get rid of parentheses

-4a+5

Back to the equation:

-(-4a+5)



We add all the numbers together, and all the variables

4a-(-4a+5)+15=0

We get rid of parentheses

4a+4a-5+15=0

We add all the numbers together, and all the variables

8a+10=0

We move all terms containing a to the left, all other terms to the right

8a=-10

a=-10/8

a=-1+1/4

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