5(a+3)=4(a-2)

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Solution for 5(a+3)=4(a-2) equation: 



5(a+3)=4(a-2)

We move all terms to the left:

5(a+3)-(4(a-2))=0

We multiply parentheses

5a-(4(a-2))+15=0



We calculate terms in parentheses: -(4(a-2)), so:

4(a-2)

We multiply parentheses

4a-8

Back to the equation:

-(4a-8)



We get rid of parentheses

5a-4a+8+15=0

We add all the numbers together, and all the variables

a+23=0

We move all terms containing a to the left, all other terms to the right

a=-23

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