5(a+b)+3(b+c)=4(b-c)

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Solution for 5(a+b)+3(b+c)=4(b-c) equation:


Simplifying
5(a + b) + 3(b + c) = 4(b + -1c)
(a * 5 + b * 5) + 3(b + c) = 4(b + -1c)
(5a + 5b) + 3(b + c) = 4(b + -1c)
5a + 5b + (b * 3 + c * 3) = 4(b + -1c)
5a + 5b + (3b + 3c) = 4(b + -1c)

Combine like terms: 5b + 3b = 8b
5a + 8b + 3c = 4(b + -1c)
5a + 8b + 3c = (b * 4 + -1c * 4)
5a + 8b + 3c = (4b + -4c)

Solving
5a + 8b + 3c = 4b + -4c

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-8b' to each side of the equation.
5a + 8b + -8b + 3c = 4b + -8b + -4c

Combine like terms: 8b + -8b = 0
5a + 0 + 3c = 4b + -8b + -4c
5a + 3c = 4b + -8b + -4c

Combine like terms: 4b + -8b = -4b
5a + 3c = -4b + -4c

Add '-3c' to each side of the equation.
5a + 3c + -3c = -4b + -4c + -3c

Combine like terms: 3c + -3c = 0
5a + 0 = -4b + -4c + -3c
5a = -4b + -4c + -3c

Combine like terms: -4c + -3c = -7c
5a = -4b + -7c

Divide each side by '5'.
a = -0.8b + -1.4c

Simplifying
a = -0.8b + -1.4c

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