5(a-1)+3(a-1)=4(3-a)+3(4a-2)

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Solution for 5(a-1)+3(a-1)=4(3-a)+3(4a-2) equation: 



5(a-1)+3(a-1)=4(3-a)+3(4a-2)

We move all terms to the left:

5(a-1)+3(a-1)-(4(3-a)+3(4a-2))=0

We add all the numbers together, and all the variables

5(a-1)+3(a-1)-(4(-1a+3)+3(4a-2))=0

We multiply parentheses

5a+3a-(4(-1a+3)+3(4a-2))-5-3=0



We calculate terms in parentheses: -(4(-1a+3)+3(4a-2)), so:

4(-1a+3)+3(4a-2)

We multiply parentheses

-4a+12a+12-6

We add all the numbers together, and all the variables

8a+6

Back to the equation:

-(8a+6)



We add all the numbers together, and all the variables

8a-(8a+6)-8=0

We get rid of parentheses

8a-8a-6-8=0

We add all the numbers together, and all the variables

-14!=0

There is no solution for this equation

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