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5(a-1)-3(2-a)=3(2a-4)+2(25-5a)
We move all terms to the left:
5(a-1)-3(2-a)-(3(2a-4)+2(25-5a))=0
We add all the numbers together, and all the variables
5(a-1)-3(-1a+2)-(3(2a-4)+2(-5a+25))=0
We multiply parentheses
5a+3a-(3(2a-4)+2(-5a+25))-5-6=0
We calculate terms in parentheses: -(3(2a-4)+2(-5a+25)), so:We add all the numbers together, and all the variables
3(2a-4)+2(-5a+25)
We multiply parentheses
6a-10a-12+50
We add all the numbers together, and all the variables
-4a+38
Back to the equation:
-(-4a+38)
8a-(-4a+38)-11=0
We get rid of parentheses
8a+4a-38-11=0
We add all the numbers together, and all the variables
12a-49=0
We move all terms containing a to the left, all other terms to the right
12a=49
a=49/12
a=4+1/12
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