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5(a-1)=4(a+1)
We move all terms to the left:
5(a-1)-(4(a+1))=0
We multiply parentheses
5a-(4(a+1))-5=0
We calculate terms in parentheses: -(4(a+1)), so:We get rid of parentheses
4(a+1)
We multiply parentheses
4a+4
Back to the equation:
-(4a+4)
5a-4a-4-5=0
We add all the numbers together, and all the variables
a-9=0
We move all terms containing a to the left, all other terms to the right
a=9
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