5(a-1)=4a(a+1)

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Solution for 5(a-1)=4a(a+1) equation: 



5(a-1)=4a(a+1)

We move all terms to the left:

5(a-1)-(4a(a+1))=0

We multiply parentheses

5a-(4a(a+1))-5=0



We calculate terms in parentheses: -(4a(a+1)), so:

4a(a+1)

We multiply parentheses

4a^2+4a

Back to the equation:

-(4a^2+4a)



We get rid of parentheses

-4a^2+5a-4a-5=0

We add all the numbers together, and all the variables

-4a^2+a-5=0

a = -4; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-4)·(-5)
Δ = -79
Delta is less than zero, so there is no solution for the equation

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