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5(a-2)+5a=3(3a+5)
We move all terms to the left:
5(a-2)+5a-(3(3a+5))=0
We add all the numbers together, and all the variables
5a+5(a-2)-(3(3a+5))=0
We multiply parentheses
5a+5a-(3(3a+5))-10=0
We calculate terms in parentheses: -(3(3a+5)), so:We add all the numbers together, and all the variables
3(3a+5)
We multiply parentheses
9a+15
Back to the equation:
-(9a+15)
10a-(9a+15)-10=0
We get rid of parentheses
10a-9a-15-10=0
We add all the numbers together, and all the variables
a-25=0
We move all terms containing a to the left, all other terms to the right
a=25
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