5(a-2)-7=2(a-4)+5

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Solution for 5(a-2)-7=2(a-4)+5 equation: 



5(a-2)-7=2(a-4)+5

We move all terms to the left:

5(a-2)-7-(2(a-4)+5)=0

We multiply parentheses

5a-(2(a-4)+5)-10-7=0



We calculate terms in parentheses: -(2(a-4)+5), so:

2(a-4)+5

We multiply parentheses

2a-8+5

We add all the numbers together, and all the variables

2a-3

Back to the equation:

-(2a-3)



We add all the numbers together, and all the variables

5a-(2a-3)-17=0

We get rid of parentheses

5a-2a+3-17=0

We add all the numbers together, and all the variables

3a-14=0

We move all terms containing a to the left, all other terms to the right

3a=14

a=14/3

a=4+2/3

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