5(a-4)(a+4)=0

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Solution for 5(a-4)(a+4)=0 equation:


Simplifying
5(a + -4)(a + 4) = 0

Reorder the terms:
5(-4 + a)(a + 4) = 0

Reorder the terms:
5(-4 + a)(4 + a) = 0

Multiply (-4 + a) * (4 + a)
5(-4(4 + a) + a(4 + a)) = 0
5((4 * -4 + a * -4) + a(4 + a)) = 0
5((-16 + -4a) + a(4 + a)) = 0
5(-16 + -4a + (4 * a + a * a)) = 0
5(-16 + -4a + (4a + a2)) = 0

Combine like terms: -4a + 4a = 0
5(-16 + 0 + a2) = 0
5(-16 + a2) = 0
(-16 * 5 + a2 * 5) = 0
(-80 + 5a2) = 0

Solving
-80 + 5a2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '80' to each side of the equation.
-80 + 80 + 5a2 = 0 + 80

Combine like terms: -80 + 80 = 0
0 + 5a2 = 0 + 80
5a2 = 0 + 80

Combine like terms: 0 + 80 = 80
5a2 = 80

Divide each side by '5'.
a2 = 16

Simplifying
a2 = 16

Take the square root of each side:
a = {-4, 4}

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