5(a-6)+10=3(a-4)

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Solution for 5(a-6)+10=3(a-4) equation:


Simplifying
5(a + -6) + 10 = 3(a + -4)

Reorder the terms:
5(-6 + a) + 10 = 3(a + -4)
(-6 * 5 + a * 5) + 10 = 3(a + -4)
(-30 + 5a) + 10 = 3(a + -4)

Reorder the terms:
-30 + 10 + 5a = 3(a + -4)

Combine like terms: -30 + 10 = -20
-20 + 5a = 3(a + -4)

Reorder the terms:
-20 + 5a = 3(-4 + a)
-20 + 5a = (-4 * 3 + a * 3)
-20 + 5a = (-12 + 3a)

Solving
-20 + 5a = -12 + 3a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3a' to each side of the equation.
-20 + 5a + -3a = -12 + 3a + -3a

Combine like terms: 5a + -3a = 2a
-20 + 2a = -12 + 3a + -3a

Combine like terms: 3a + -3a = 0
-20 + 2a = -12 + 0
-20 + 2a = -12

Add '20' to each side of the equation.
-20 + 20 + 2a = -12 + 20

Combine like terms: -20 + 20 = 0
0 + 2a = -12 + 20
2a = -12 + 20

Combine like terms: -12 + 20 = 8
2a = 8

Divide each side by '2'.
a = 4

Simplifying
a = 4

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