5(b+1)+b=5(b-2)-1

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Solution for 5(b+1)+b=5(b-2)-1 equation:


Simplifying
5(b + 1) + b = 5(b + -2) + -1

Reorder the terms:
5(1 + b) + b = 5(b + -2) + -1
(1 * 5 + b * 5) + b = 5(b + -2) + -1
(5 + 5b) + b = 5(b + -2) + -1

Combine like terms: 5b + b = 6b
5 + 6b = 5(b + -2) + -1

Reorder the terms:
5 + 6b = 5(-2 + b) + -1
5 + 6b = (-2 * 5 + b * 5) + -1
5 + 6b = (-10 + 5b) + -1

Reorder the terms:
5 + 6b = -10 + -1 + 5b

Combine like terms: -10 + -1 = -11
5 + 6b = -11 + 5b

Solving
5 + 6b = -11 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
5 + 6b + -5b = -11 + 5b + -5b

Combine like terms: 6b + -5b = 1b
5 + 1b = -11 + 5b + -5b

Combine like terms: 5b + -5b = 0
5 + 1b = -11 + 0
5 + 1b = -11

Add '-5' to each side of the equation.
5 + -5 + 1b = -11 + -5

Combine like terms: 5 + -5 = 0
0 + 1b = -11 + -5
1b = -11 + -5

Combine like terms: -11 + -5 = -16
1b = -16

Divide each side by '1'.
b = -16

Simplifying
b = -16

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