5(b+1)-6=3(b+1)

Solution for 5(b+1)-6=3(b+1) equation:

Simplifying
5(b + 1) + -6 = 3(b + 1)

Reorder the terms:
5(1 + b) + -6 = 3(b + 1)
(1 * 5 + b * 5) + -6 = 3(b + 1)
(5 + 5b) + -6 = 3(b + 1)

Reorder the terms:
5 + -6 + 5b = 3(b + 1)

Combine like terms: 5 + -6 = -1
-1 + 5b = 3(b + 1)

Reorder the terms:
-1 + 5b = 3(1 + b)
-1 + 5b = (1 * 3 + b * 3)
-1 + 5b = (3 + 3b)

Solving
-1 + 5b = 3 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-1 + 5b + -3b = 3 + 3b + -3b

Combine like terms: 5b + -3b = 2b
-1 + 2b = 3 + 3b + -3b

Combine like terms: 3b + -3b = 0
-1 + 2b = 3 + 0
-1 + 2b = 3

Add '1' to each side of the equation.
-1 + 1 + 2b = 3 + 1

Combine like terms: -1 + 1 = 0
0 + 2b = 3 + 1
2b = 3 + 1

Combine like terms: 3 + 1 = 4
2b = 4

Divide each side by '2'.
b = 2

Simplifying
b = 2