5(b+1)=2b+32

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Solution for 5(b+1)=2b+32 equation:


Simplifying
5(b + 1) = 2b + 32

Reorder the terms:
5(1 + b) = 2b + 32
(1 * 5 + b * 5) = 2b + 32
(5 + 5b) = 2b + 32

Reorder the terms:
5 + 5b = 32 + 2b

Solving
5 + 5b = 32 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
5 + 5b + -2b = 32 + 2b + -2b

Combine like terms: 5b + -2b = 3b
5 + 3b = 32 + 2b + -2b

Combine like terms: 2b + -2b = 0
5 + 3b = 32 + 0
5 + 3b = 32

Add '-5' to each side of the equation.
5 + -5 + 3b = 32 + -5

Combine like terms: 5 + -5 = 0
0 + 3b = 32 + -5
3b = 32 + -5

Combine like terms: 32 + -5 = 27
3b = 27

Divide each side by '3'.
b = 9

Simplifying
b = 9

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