5(b+1)=4(b+3)

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Solution for 5(b+1)=4(b+3) equation:


Simplifying
5(b + 1) = 4(b + 3)

Reorder the terms:
5(1 + b) = 4(b + 3)
(1 * 5 + b * 5) = 4(b + 3)
(5 + 5b) = 4(b + 3)

Reorder the terms:
5 + 5b = 4(3 + b)
5 + 5b = (3 * 4 + b * 4)
5 + 5b = (12 + 4b)

Solving
5 + 5b = 12 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
5 + 5b + -4b = 12 + 4b + -4b

Combine like terms: 5b + -4b = 1b
5 + 1b = 12 + 4b + -4b

Combine like terms: 4b + -4b = 0
5 + 1b = 12 + 0
5 + 1b = 12

Add '-5' to each side of the equation.
5 + -5 + 1b = 12 + -5

Combine like terms: 5 + -5 = 0
0 + 1b = 12 + -5
1b = 12 + -5

Combine like terms: 12 + -5 = 7
1b = 7

Divide each side by '1'.
b = 7

Simplifying
b = 7

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