5(b+10)+8=8b-1

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Solution for 5(b+10)+8=8b-1 equation: 



5(b+10)+8=8b-1

We move all terms to the left:

5(b+10)+8-(8b-1)=0

We multiply parentheses

5b-(8b-1)+50+8=0

We get rid of parentheses

5b-8b+1+50+8=0

We add all the numbers together, and all the variables

-3b+59=0

We move all terms containing b to the left, all other terms to the right

-3b=-59

b=-59/-3

b=19+2/3

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