5(b+2)-3=57

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Solution for 5(b+2)-3=57 equation: 



5(b+2)-3=57

We move all terms to the left:

5(b+2)-3-(57)=0

We add all the numbers together, and all the variables

5(b+2)-60=0

We multiply parentheses

5b+10-60=0

We add all the numbers together, and all the variables

5b-50=0

We move all terms containing b to the left, all other terms to the right

5b=50

b=50/5

b=10

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