5(b+2)=9(b+1)

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Solution for 5(b+2)=9(b+1) equation:


Simplifying
5(b + 2) = 9(b + 1)

Reorder the terms:
5(2 + b) = 9(b + 1)
(2 * 5 + b * 5) = 9(b + 1)
(10 + 5b) = 9(b + 1)

Reorder the terms:
10 + 5b = 9(1 + b)
10 + 5b = (1 * 9 + b * 9)
10 + 5b = (9 + 9b)

Solving
10 + 5b = 9 + 9b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-9b' to each side of the equation.
10 + 5b + -9b = 9 + 9b + -9b

Combine like terms: 5b + -9b = -4b
10 + -4b = 9 + 9b + -9b

Combine like terms: 9b + -9b = 0
10 + -4b = 9 + 0
10 + -4b = 9

Add '-10' to each side of the equation.
10 + -10 + -4b = 9 + -10

Combine like terms: 10 + -10 = 0
0 + -4b = 9 + -10
-4b = 9 + -10

Combine like terms: 9 + -10 = -1
-4b = -1

Divide each side by '-4'.
b = 0.25

Simplifying
b = 0.25

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