5(b+3)+3(b+1)=34

Solution for 5(b+3)+3(b+1)=34 equation:

Simplifying
5(b + 3) + 3(b + 1) = 34

Reorder the terms:
5(3 + b) + 3(b + 1) = 34
(3 * 5 + b * 5) + 3(b + 1) = 34
(15 + 5b) + 3(b + 1) = 34

Reorder the terms:
15 + 5b + 3(1 + b) = 34
15 + 5b + (1 * 3 + b * 3) = 34
15 + 5b + (3 + 3b) = 34

Reorder the terms:
15 + 3 + 5b + 3b = 34

Combine like terms: 15 + 3 = 18
18 + 5b + 3b = 34

Combine like terms: 5b + 3b = 8b
18 + 8b = 34

Solving
18 + 8b = 34

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-18' to each side of the equation.
18 + -18 + 8b = 34 + -18

Combine like terms: 18 + -18 = 0
0 + 8b = 34 + -18
8b = 34 + -18

Combine like terms: 34 + -18 = 16
8b = 16

Divide each side by '8'.
b = 2

Simplifying
b = 2