5(b+3)-3b+5=4(b-1)

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Solution for 5(b+3)-3b+5=4(b-1) equation:


Simplifying
5(b + 3) + -3b + 5 = 4(b + -1)

Reorder the terms:
5(3 + b) + -3b + 5 = 4(b + -1)
(3 * 5 + b * 5) + -3b + 5 = 4(b + -1)
(15 + 5b) + -3b + 5 = 4(b + -1)

Reorder the terms:
15 + 5 + 5b + -3b = 4(b + -1)

Combine like terms: 15 + 5 = 20
20 + 5b + -3b = 4(b + -1)

Combine like terms: 5b + -3b = 2b
20 + 2b = 4(b + -1)

Reorder the terms:
20 + 2b = 4(-1 + b)
20 + 2b = (-1 * 4 + b * 4)
20 + 2b = (-4 + 4b)

Solving
20 + 2b = -4 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
20 + 2b + -4b = -4 + 4b + -4b

Combine like terms: 2b + -4b = -2b
20 + -2b = -4 + 4b + -4b

Combine like terms: 4b + -4b = 0
20 + -2b = -4 + 0
20 + -2b = -4

Add '-20' to each side of the equation.
20 + -20 + -2b = -4 + -20

Combine like terms: 20 + -20 = 0
0 + -2b = -4 + -20
-2b = -4 + -20

Combine like terms: -4 + -20 = -24
-2b = -24

Divide each side by '-2'.
b = 12

Simplifying
b = 12

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