5(b+3)-5=35

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Solution for 5(b+3)-5=35 equation: 



5(b+3)-5=35

We move all terms to the left:

5(b+3)-5-(35)=0

We add all the numbers together, and all the variables

5(b+3)-40=0

We multiply parentheses

5b+15-40=0

We add all the numbers together, and all the variables

5b-25=0

We move all terms containing b to the left, all other terms to the right

5b=25

b=25/5

b=5

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