5(b+3)=2(b+4)+13

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Solution for 5(b+3)=2(b+4)+13 equation:


Simplifying
5(b + 3) = 2(b + 4) + 13

Reorder the terms:
5(3 + b) = 2(b + 4) + 13
(3 * 5 + b * 5) = 2(b + 4) + 13
(15 + 5b) = 2(b + 4) + 13

Reorder the terms:
15 + 5b = 2(4 + b) + 13
15 + 5b = (4 * 2 + b * 2) + 13
15 + 5b = (8 + 2b) + 13

Reorder the terms:
15 + 5b = 8 + 13 + 2b

Combine like terms: 8 + 13 = 21
15 + 5b = 21 + 2b

Solving
15 + 5b = 21 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
15 + 5b + -2b = 21 + 2b + -2b

Combine like terms: 5b + -2b = 3b
15 + 3b = 21 + 2b + -2b

Combine like terms: 2b + -2b = 0
15 + 3b = 21 + 0
15 + 3b = 21

Add '-15' to each side of the equation.
15 + -15 + 3b = 21 + -15

Combine like terms: 15 + -15 = 0
0 + 3b = 21 + -15
3b = 21 + -15

Combine like terms: 21 + -15 = 6
3b = 6

Divide each side by '3'.
b = 2

Simplifying
b = 2

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