5(b+3)=3b-1

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Solution for 5(b+3)=3b-1 equation: 



5(b+3)=3b-1

We move all terms to the left:

5(b+3)-(3b-1)=0

We multiply parentheses

5b-(3b-1)+15=0

We get rid of parentheses

5b-3b+1+15=0

We add all the numbers together, and all the variables

2b+16=0

We move all terms containing b to the left, all other terms to the right

2b=-16

b=-16/2

b=-8

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