5(b+3)=7(-10+12b)+6b

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Solution for 5(b+3)=7(-10+12b)+6b equation:



5(b+3)=7(-10+12b)+6b
We move all terms to the left:
5(b+3)-(7(-10+12b)+6b)=0
We add all the numbers together, and all the variables
5(b+3)-(7(12b-10)+6b)=0
We multiply parentheses
5b-(7(12b-10)+6b)+15=0
We calculate terms in parentheses: -(7(12b-10)+6b), so:
7(12b-10)+6b
We add all the numbers together, and all the variables
6b+7(12b-10)
We multiply parentheses
6b+84b-70
We add all the numbers together, and all the variables
90b-70
Back to the equation:
-(90b-70)
We get rid of parentheses
5b-90b+70+15=0
We add all the numbers together, and all the variables
-85b+85=0
We move all terms containing b to the left, all other terms to the right
-85b=-85
b=-85/-85
b=1

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