5(b+3)=7(-10+12b)+6b

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Solution for 5(b+3)=7(-10+12b)+6b equation: 



5(b+3)=7(-10+12b)+6b

We move all terms to the left:

5(b+3)-(7(-10+12b)+6b)=0

We add all the numbers together, and all the variables

5(b+3)-(7(12b-10)+6b)=0

We multiply parentheses

5b-(7(12b-10)+6b)+15=0



We calculate terms in parentheses: -(7(12b-10)+6b), so:

7(12b-10)+6b

We add all the numbers together, and all the variables

6b+7(12b-10)

We multiply parentheses

6b+84b-70

We add all the numbers together, and all the variables

90b-70

Back to the equation:

-(90b-70)



We get rid of parentheses

5b-90b+70+15=0

We add all the numbers together, and all the variables

-85b+85=0

We move all terms containing b to the left, all other terms to the right

-85b=-85

b=-85/-85

b=1

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