5(b+4)=7-(-5b-13)

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Solution for 5(b+4)=7-(-5b-13) equation: 



5(b+4)=7-(-5b-13)

We move all terms to the left:

5(b+4)-(7-(-5b-13))=0

We multiply parentheses

5b-(7-(-5b-13))+20=0



We calculate terms in parentheses: -(7-(-5b-13)), so:

7-(-5b-13)

determiningTheFunctionDomain
-(-5b-13)+7

We get rid of parentheses

5b+13+7

We add all the numbers together, and all the variables

5b+20

Back to the equation:

-(5b+20)



We get rid of parentheses

5b-5b-20+20=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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