5(b+c)-4(3b-2c+1)=

Solution for 5(b+c)-4(3b-2c+1)= equation:

Simplifying
5(b + c) + -4(3b + -2c + 1) = 0
(b * 5 + c * 5) + -4(3b + -2c + 1) = 0
(5b + 5c) + -4(3b + -2c + 1) = 0

Reorder the terms:
5b + 5c + -4(1 + 3b + -2c) = 0
5b + 5c + (1 * -4 + 3b * -4 + -2c * -4) = 0
5b + 5c + (-4 + -12b + 8c) = 0

Reorder the terms:
-4 + 5b + -12b + 5c + 8c = 0

Combine like terms: 5b + -12b = -7b
-4 + -7b + 5c + 8c = 0

Combine like terms: 5c + 8c = 13c
-4 + -7b + 13c = 0

Solving
-4 + -7b + 13c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + -7b + 4 + 13c = 0 + 4

Reorder the terms:
-4 + 4 + -7b + 13c = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -7b + 13c = 0 + 4
-7b + 13c = 0 + 4

Combine like terms: 0 + 4 = 4
-7b + 13c = 4

Add '-13c' to each side of the equation.
-7b + 13c + -13c = 4 + -13c

Combine like terms: 13c + -13c = 0
-7b + 0 = 4 + -13c
-7b = 4 + -13c

Divide each side by '-7'.
b = -0.5714285714 + 1.857142857c

Simplifying
b = -0.5714285714 + 1.857142857c