5(b+c)=7(b-c)

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Solution for 5(b+c)=7(b-c) equation:


Simplifying
5(b + c) = 7(b + -1c)
(b * 5 + c * 5) = 7(b + -1c)
(5b + 5c) = 7(b + -1c)
5b + 5c = (b * 7 + -1c * 7)
5b + 5c = (7b + -7c)

Solving
5b + 5c = 7b + -7c

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-7b' to each side of the equation.
5b + -7b + 5c = 7b + -7b + -7c

Combine like terms: 5b + -7b = -2b
-2b + 5c = 7b + -7b + -7c

Combine like terms: 7b + -7b = 0
-2b + 5c = 0 + -7c
-2b + 5c = -7c

Add '-5c' to each side of the equation.
-2b + 5c + -5c = -7c + -5c

Combine like terms: 5c + -5c = 0
-2b + 0 = -7c + -5c
-2b = -7c + -5c

Combine like terms: -7c + -5c = -12c
-2b = -12c

Divide each side by '-2'.
b = 6c

Simplifying
b = 6c

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