5(b-1)+4=b-05

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Solution for 5(b-1)+4=b-05 equation: 



5(b-1)+4=b-05

We move all terms to the left:

5(b-1)+4-(b-05)=0

We add all the numbers together, and all the variables

5(b-1)-(b-5)+4=0

We multiply parentheses

5b-(b-5)-5+4=0

We get rid of parentheses

5b-b+5-5+4=0

We add all the numbers together, and all the variables

4b+4=0

We move all terms containing b to the left, all other terms to the right

4b=-4

b=-4/4

b=-1

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