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5(b-1)-3b=7b-5(1+b)
We move all terms to the left:
5(b-1)-3b-(7b-5(1+b))=0
We add all the numbers together, and all the variables
5(b-1)-3b-(7b-5(b+1))=0
We add all the numbers together, and all the variables
-3b+5(b-1)-(7b-5(b+1))=0
We multiply parentheses
-3b+5b-(7b-5(b+1))-5=0
We calculate terms in parentheses: -(7b-5(b+1)), so:We add all the numbers together, and all the variables
7b-5(b+1)
We multiply parentheses
7b-5b-5
We add all the numbers together, and all the variables
2b-5
Back to the equation:
-(2b-5)
2b-(2b-5)-5=0
We get rid of parentheses
2b-2b+5-5=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0
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