5(b-1)-3b=7b-5(1+b)

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Solution for 5(b-1)-3b=7b-5(1+b) equation: 



5(b-1)-3b=7b-5(1+b)

We move all terms to the left:

5(b-1)-3b-(7b-5(1+b))=0

We add all the numbers together, and all the variables

5(b-1)-3b-(7b-5(b+1))=0

We add all the numbers together, and all the variables

-3b+5(b-1)-(7b-5(b+1))=0

We multiply parentheses

-3b+5b-(7b-5(b+1))-5=0



We calculate terms in parentheses: -(7b-5(b+1)), so:

7b-5(b+1)

We multiply parentheses

7b-5b-5

We add all the numbers together, and all the variables

2b-5

Back to the equation:

-(2b-5)



We add all the numbers together, and all the variables

2b-(2b-5)-5=0

We get rid of parentheses

2b-2b+5-5=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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