5(b-1)=-(b-4)-8

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Solution for 5(b-1)=-(b-4)-8 equation: 



5(b-1)=-(b-4)-8

We move all terms to the left:

5(b-1)-(-(b-4)-8)=0

We multiply parentheses

5b-(-(b-4)-8)-5=0



We calculate terms in parentheses: -(-(b-4)-8), so:

-(b-4)-8

We get rid of parentheses

-b+4-8

We add all the numbers together, and all the variables

-1b-4

Back to the equation:

-(-1b-4)



We get rid of parentheses

5b+1b+4-5=0

We add all the numbers together, and all the variables

6b-1=0

We move all terms containing b to the left, all other terms to the right

6b=1

b=1/6

b=1/6

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