5(b-1)=b+2

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Solution for 5(b-1)=b+2 equation: 



5(b-1)=b+2

We move all terms to the left:

5(b-1)-(b+2)=0

We multiply parentheses

5b-(b+2)-5=0

We get rid of parentheses

5b-b-2-5=0

We add all the numbers together, and all the variables

4b-7=0

We move all terms containing b to the left, all other terms to the right

4b=7

b=7/4

b=1+3/4

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