5(b-2)+(b+3)=2(2b+1)-9

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Solution for 5(b-2)+(b+3)=2(2b+1)-9 equation: 



5(b-2)+(b+3)=2(2b+1)-9

We move all terms to the left:

5(b-2)+(b+3)-(2(2b+1)-9)=0

We multiply parentheses

5b+(b+3)-(2(2b+1)-9)-10=0

We get rid of parentheses

5b+b-(2(2b+1)-9)+3-10=0



We calculate terms in parentheses: -(2(2b+1)-9), so:

2(2b+1)-9

We multiply parentheses

4b+2-9

We add all the numbers together, and all the variables

4b-7

Back to the equation:

-(4b-7)



We add all the numbers together, and all the variables

6b-(4b-7)-7=0

We get rid of parentheses

6b-4b+7-7=0

We add all the numbers together, and all the variables

2b=0

b=0/2

b=0

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