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5(b-2)+(b+3)=2(2b+1)-9
We move all terms to the left:
5(b-2)+(b+3)-(2(2b+1)-9)=0
We multiply parentheses
5b+(b+3)-(2(2b+1)-9)-10=0
We get rid of parentheses
5b+b-(2(2b+1)-9)+3-10=0
We calculate terms in parentheses: -(2(2b+1)-9), so:We add all the numbers together, and all the variables
2(2b+1)-9
We multiply parentheses
4b+2-9
We add all the numbers together, and all the variables
4b-7
Back to the equation:
-(4b-7)
6b-(4b-7)-7=0
We get rid of parentheses
6b-4b+7-7=0
We add all the numbers together, and all the variables
2b=0
b=0/2
b=0
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