5(b-3)+10=3(b+2)-1

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Solution for 5(b-3)+10=3(b+2)-1 equation: 



5(b-3)+10=3(b+2)-1

We move all terms to the left:

5(b-3)+10-(3(b+2)-1)=0

We multiply parentheses

5b-(3(b+2)-1)-15+10=0



We calculate terms in parentheses: -(3(b+2)-1), so:

3(b+2)-1

We multiply parentheses

3b+6-1

We add all the numbers together, and all the variables

3b+5

Back to the equation:

-(3b+5)



We add all the numbers together, and all the variables

5b-(3b+5)-5=0

We get rid of parentheses

5b-3b-5-5=0

We add all the numbers together, and all the variables

2b-10=0

We move all terms containing b to the left, all other terms to the right

2b=10

b=10/2

b=5

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