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5(b-3)+8b=6b-3+b
We move all terms to the left:
5(b-3)+8b-(6b-3+b)=0
We add all the numbers together, and all the variables
5(b-3)+8b-(7b-3)=0
We add all the numbers together, and all the variables
8b+5(b-3)-(7b-3)=0
We multiply parentheses
8b+5b-(7b-3)-15=0
We get rid of parentheses
8b+5b-7b+3-15=0
We add all the numbers together, and all the variables
6b-12=0
We move all terms containing b to the left, all other terms to the right
6b=12
b=12/6
b=2
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