5(b-3)=7(b-2)

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Solution for 5(b-3)=7(b-2) equation:


Simplifying
5(b + -3) = 7(b + -2)

Reorder the terms:
5(-3 + b) = 7(b + -2)
(-3 * 5 + b * 5) = 7(b + -2)
(-15 + 5b) = 7(b + -2)

Reorder the terms:
-15 + 5b = 7(-2 + b)
-15 + 5b = (-2 * 7 + b * 7)
-15 + 5b = (-14 + 7b)

Solving
-15 + 5b = -14 + 7b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-7b' to each side of the equation.
-15 + 5b + -7b = -14 + 7b + -7b

Combine like terms: 5b + -7b = -2b
-15 + -2b = -14 + 7b + -7b

Combine like terms: 7b + -7b = 0
-15 + -2b = -14 + 0
-15 + -2b = -14

Add '15' to each side of the equation.
-15 + 15 + -2b = -14 + 15

Combine like terms: -15 + 15 = 0
0 + -2b = -14 + 15
-2b = -14 + 15

Combine like terms: -14 + 15 = 1
-2b = 1

Divide each side by '-2'.
b = -0.5

Simplifying
b = -0.5

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