5(b-4)+2b=6(b+4)

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Solution for 5(b-4)+2b=6(b+4) equation: 



5(b-4)+2b=6(b+4)

We move all terms to the left:

5(b-4)+2b-(6(b+4))=0

We add all the numbers together, and all the variables

2b+5(b-4)-(6(b+4))=0

We multiply parentheses

2b+5b-(6(b+4))-20=0



We calculate terms in parentheses: -(6(b+4)), so:

6(b+4)

We multiply parentheses

6b+24

Back to the equation:

-(6b+24)



We add all the numbers together, and all the variables

7b-(6b+24)-20=0

We get rid of parentheses

7b-6b-24-20=0

We add all the numbers together, and all the variables

b-44=0

We move all terms containing b to the left, all other terms to the right

b=44

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