5(b-4)+b=(-8)

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Solution for 5(b-4)+b=(-8) equation: 



5(b-4)+b=(-8)

We move all terms to the left:

5(b-4)+b-((-8))=0

We add all the numbers together, and all the variables

b+5(b-4)+8=0

We multiply parentheses

b+5b-20+8=0

We add all the numbers together, and all the variables

6b-12=0

We move all terms containing b to the left, all other terms to the right

6b=12

b=12/6

b=2

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