5(b-5)=20+b

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Solution for 5(b-5)=20+b equation: 



5(b-5)=20+b

We move all terms to the left:

5(b-5)-(20+b)=0

We add all the numbers together, and all the variables

5(b-5)-(b+20)=0

We multiply parentheses

5b-(b+20)-25=0

We get rid of parentheses

5b-b-20-25=0

We add all the numbers together, and all the variables

4b-45=0

We move all terms containing b to the left, all other terms to the right

4b=45

b=45/4

b=11+1/4

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