5(b-7)=7b-29

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Solution for 5(b-7)=7b-29 equation: 



5(b-7)=7b-29

We move all terms to the left:

5(b-7)-(7b-29)=0

We multiply parentheses

5b-(7b-29)-35=0

We get rid of parentheses

5b-7b+29-35=0

We add all the numbers together, and all the variables

-2b-6=0

We move all terms containing b to the left, all other terms to the right

-2b=6

b=6/-2

b=-3

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