5(b-9)+4(3b+9)=6(4b-5)-7b+21

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Solution for 5(b-9)+4(3b+9)=6(4b-5)-7b+21 equation: 



5(b-9)+4(3b+9)=6(4b-5)-7b+21

We move all terms to the left:

5(b-9)+4(3b+9)-(6(4b-5)-7b+21)=0

We multiply parentheses

5b+12b-(6(4b-5)-7b+21)-45+36=0



We calculate terms in parentheses: -(6(4b-5)-7b+21), so:

6(4b-5)-7b+21

We add all the numbers together, and all the variables

-7b+6(4b-5)+21

We multiply parentheses

-7b+24b-30+21

We add all the numbers together, and all the variables

17b-9

Back to the equation:

-(17b-9)



We add all the numbers together, and all the variables

17b-(17b-9)-9=0

We get rid of parentheses

17b-17b+9-9=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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