5(c+1)/6=2c-3

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Solution for 5(c+1)/6=2c-3 equation:



5(c+1)/6=2c-3
We move all terms to the left:
5(c+1)/6-(2c-3)=0
We get rid of parentheses
5(c+1)/6-2c+3=0
We multiply all the terms by the denominator
5(c+1)-2c*6+3*6=0
We add all the numbers together, and all the variables
5(c+1)-2c*6+18=0
We multiply parentheses
5c-2c*6+5+18=0
Wy multiply elements
5c-12c+5+18=0
We add all the numbers together, and all the variables
-7c+23=0
We move all terms containing c to the left, all other terms to the right
-7c=-23
c=-23/-7
c=3+2/7

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