5(c+1)=6(c+2)

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Solution for 5(c+1)=6(c+2) equation:


Simplifying
5(c + 1) = 6(c + 2)

Reorder the terms:
5(1 + c) = 6(c + 2)
(1 * 5 + c * 5) = 6(c + 2)
(5 + 5c) = 6(c + 2)

Reorder the terms:
5 + 5c = 6(2 + c)
5 + 5c = (2 * 6 + c * 6)
5 + 5c = (12 + 6c)

Solving
5 + 5c = 12 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
5 + 5c + -6c = 12 + 6c + -6c

Combine like terms: 5c + -6c = -1c
5 + -1c = 12 + 6c + -6c

Combine like terms: 6c + -6c = 0
5 + -1c = 12 + 0
5 + -1c = 12

Add '-5' to each side of the equation.
5 + -5 + -1c = 12 + -5

Combine like terms: 5 + -5 = 0
0 + -1c = 12 + -5
-1c = 12 + -5

Combine like terms: 12 + -5 = 7
-1c = 7

Divide each side by '-1'.
c = -7

Simplifying
c = -7

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