5(c+12)+7=10c-10

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Solution for 5(c+12)+7=10c-10 equation: 



5(c+12)+7=10c-10

We move all terms to the left:

5(c+12)+7-(10c-10)=0

We multiply parentheses

5c-(10c-10)+60+7=0

We get rid of parentheses

5c-10c+10+60+7=0

We add all the numbers together, and all the variables

-5c+77=0

We move all terms containing c to the left, all other terms to the right

-5c=-77

c=-77/-5

c=15+2/5

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