5(c+2)+4=2(22+7)+c

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Solution for 5(c+2)+4=2(22+7)+c equation:


Simplifying
5(c + 2) + 4 = 2(22 + 7) + c

Reorder the terms:
5(2 + c) + 4 = 2(22 + 7) + c
(2 * 5 + c * 5) + 4 = 2(22 + 7) + c
(10 + 5c) + 4 = 2(22 + 7) + c

Reorder the terms:
10 + 4 + 5c = 2(22 + 7) + c

Combine like terms: 10 + 4 = 14
14 + 5c = 2(22 + 7) + c

Combine like terms: 22 + 7 = 29
14 + 5c = 2(29) + c

Multiply 2 * 29
14 + 5c = 58 + c

Solving
14 + 5c = 58 + c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
14 + 5c + -1c = 58 + c + -1c

Combine like terms: 5c + -1c = 4c
14 + 4c = 58 + c + -1c

Combine like terms: c + -1c = 0
14 + 4c = 58 + 0
14 + 4c = 58

Add '-14' to each side of the equation.
14 + -14 + 4c = 58 + -14

Combine like terms: 14 + -14 = 0
0 + 4c = 58 + -14
4c = 58 + -14

Combine like terms: 58 + -14 = 44
4c = 44

Divide each side by '4'.
c = 11

Simplifying
c = 11

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