5(c+2)-3c=2(c-8)+26

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Solution for 5(c+2)-3c=2(c-8)+26 equation: 



5(c+2)-3c=2(c-8)+26

We move all terms to the left:

5(c+2)-3c-(2(c-8)+26)=0

We add all the numbers together, and all the variables

-3c+5(c+2)-(2(c-8)+26)=0

We multiply parentheses

-3c+5c-(2(c-8)+26)+10=0



We calculate terms in parentheses: -(2(c-8)+26), so:

2(c-8)+26

We multiply parentheses

2c-16+26

We add all the numbers together, and all the variables

2c+10

Back to the equation:

-(2c+10)



We add all the numbers together, and all the variables

2c-(2c+10)+10=0

We get rid of parentheses

2c-2c-10+10=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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