5(c+2)=2(c+1)

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Solution for 5(c+2)=2(c+1) equation:


Simplifying
5(c + 2) = 2(c + 1)

Reorder the terms:
5(2 + c) = 2(c + 1)
(2 * 5 + c * 5) = 2(c + 1)
(10 + 5c) = 2(c + 1)

Reorder the terms:
10 + 5c = 2(1 + c)
10 + 5c = (1 * 2 + c * 2)
10 + 5c = (2 + 2c)

Solving
10 + 5c = 2 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
10 + 5c + -2c = 2 + 2c + -2c

Combine like terms: 5c + -2c = 3c
10 + 3c = 2 + 2c + -2c

Combine like terms: 2c + -2c = 0
10 + 3c = 2 + 0
10 + 3c = 2

Add '-10' to each side of the equation.
10 + -10 + 3c = 2 + -10

Combine like terms: 10 + -10 = 0
0 + 3c = 2 + -10
3c = 2 + -10

Combine like terms: 2 + -10 = -8
3c = -8

Divide each side by '3'.
c = -2.666666667

Simplifying
c = -2.666666667

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