5(c+3)+3(c+1)=14

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Solution for 5(c+3)+3(c+1)=14 equation: 



5(c+3)+3(c+1)=14

We move all terms to the left:

5(c+3)+3(c+1)-(14)=0

We multiply parentheses

5c+3c+15+3-14=0

We add all the numbers together, and all the variables

8c+4=0

We move all terms containing c to the left, all other terms to the right

8c=-4

c=-4/8

c=-1/2

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