5(c+3)-2c=4+3(2c+1)

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Solution for 5(c+3)-2c=4+3(2c+1) equation:


Simplifying
5(c + 3) + -2c = 4 + 3(2c + 1)

Reorder the terms:
5(3 + c) + -2c = 4 + 3(2c + 1)
(3 * 5 + c * 5) + -2c = 4 + 3(2c + 1)
(15 + 5c) + -2c = 4 + 3(2c + 1)

Combine like terms: 5c + -2c = 3c
15 + 3c = 4 + 3(2c + 1)

Reorder the terms:
15 + 3c = 4 + 3(1 + 2c)
15 + 3c = 4 + (1 * 3 + 2c * 3)
15 + 3c = 4 + (3 + 6c)

Combine like terms: 4 + 3 = 7
15 + 3c = 7 + 6c

Solving
15 + 3c = 7 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
15 + 3c + -6c = 7 + 6c + -6c

Combine like terms: 3c + -6c = -3c
15 + -3c = 7 + 6c + -6c

Combine like terms: 6c + -6c = 0
15 + -3c = 7 + 0
15 + -3c = 7

Add '-15' to each side of the equation.
15 + -15 + -3c = 7 + -15

Combine like terms: 15 + -15 = 0
0 + -3c = 7 + -15
-3c = 7 + -15

Combine like terms: 7 + -15 = -8
-3c = -8

Divide each side by '-3'.
c = 2.666666667

Simplifying
c = 2.666666667

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